Distance traveled at 55 mph with 5-second cushion

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Get ready for the VFIS Emergency Vehicle Driver Training (EVDT) Instructor Exam. Prepare with flashcards, multiple choice questions, hints, and explanations. Succeed on your exam!

Multiple Choice

Distance traveled at 55 mph with 5-second cushion

Explanation:
The distance covered during a 5-second cushion is found by multiplying speed by time, using consistent units. Convert 55 mph to feet per second: 55 miles per hour equals 55 × 5280 feet per hour = 290,400 ft/hour, which is 290,400 ÷ 3600 ≈ 80.7 ft/s. In 5 seconds, that’s 80.7 × 5 ≈ 403.5 feet. The closest option is 400 feet. So the distance traveled is about 400 ft.

The distance covered during a 5-second cushion is found by multiplying speed by time, using consistent units. Convert 55 mph to feet per second: 55 miles per hour equals 55 × 5280 feet per hour = 290,400 ft/hour, which is 290,400 ÷ 3600 ≈ 80.7 ft/s. In 5 seconds, that’s 80.7 × 5 ≈ 403.5 feet. The closest option is 400 feet. So the distance traveled is about 400 ft.

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